企业免费网站推广公司,网站建设环境分析,一个网站需要多少网页,深圳网站seo 乐云践新Convex Hull gay(i){0ifikxx,xk,k1iielse}求∑i1n∑j1igay(j)∑i1n(n−i1)gay(i)∑i1n(n−i1)μ2(i)i2因为μ2(n)∑i2∣nμ(i)#xff0c;容斥定理显然得到有原式∑i1n(n−i1)i2∑j2∣iμ(j)(n1)∑i1n∑j2∣iμ(j)−∑i1ni3∑j2∣iμ(j)(n1)∑j1nμ(j)∑j2∣ii2−∑j1…Convex Hull
gay(i){0ifik×x×x,xk,k1i×ielse}求∑i1n∑j1igay(j)∑i1n(n−i1)gay(i)∑i1n(n−i1)μ2(i)i2因为μ2(n)∑i2∣nμ(i)容斥定理显然得到有原式∑i1n(n−i1)i2∑j2∣iμ(j)(n1)∑i1n∑j2∣iμ(j)−∑i1ni3∑j2∣iμ(j)(n1)∑j1nμ(j)∑j2∣ii2−∑j1nμ(j)∑j2∣ii3(n1)∑j1nμ(j)∑t1nj2t2j4−∑j1nμ(j)∑t1nj2t3j6∑i1nμ(i)∑j1ni2(i4j2(n1)−i6j3)gay(i) \left\{ \begin{matrix} 0ifi k \times x \times x, x k, k 1\\ i \times ielse \end{matrix} \right\}\\ 求\sum_{i 1} ^{n} \sum_{j 1} ^{i}gay(j)\\ \sum_{i 1} ^{n}(n - i 1) gay(i)\\ \sum_{i 1} ^{n}(n - i 1)\mu ^2(i) i ^2\\ 因为\mu ^2(n) \sum_{i ^ 2 \mid n} \mu(i)容斥定理显然得到\\ 有原式 \sum_{i 1} ^{n} (n - i 1) i ^ 2 \sum_{j ^2 \mid i} \mu(j)\\ (n 1) \sum_{i 1} ^{n} \sum_{j ^ 2 \mid i} \mu(j) - \sum_{i 1} ^{n} i ^ 3 \sum_{j ^ 2 \mid i} \mu(j)\\ (n 1) \sum_{j 1} ^{\sqrt n} \mu(j) \sum_{j ^ 2 \mid i} i ^ 2 - \sum_{j 1} ^{\sqrt n} \mu(j) \sum_{j ^ 2 \mid i} i ^ 3\\ (n 1) \sum_{j 1} ^{\sqrt n} \mu(j) \sum_{t 1} ^{\frac{n}{j ^ 2}} t ^ 2 j ^ 4 - \sum_{j 1} ^{\sqrt n} \mu(j) \sum_{t 1} ^{\frac{n}{j ^ 2}} t ^ 3 j ^ 6\\ \sum_{i 1} ^{\sqrt n} \mu(i) \sum_{j 1} ^{\frac{n}{i ^ 2}}(i ^ 4 j ^ 2 (n 1) - i ^ 6 j ^ 3)\\ gay(i){0i×iifelseik×x×x,xk,k1}求i1∑nj1∑igay(j)i1∑n(n−i1)gay(i)i1∑n(n−i1)μ2(i)i2因为μ2(n)i2∣n∑μ(i)容斥定理显然得到有原式i1∑n(n−i1)i2j2∣i∑μ(j)(n1)i1∑nj2∣i∑μ(j)−i1∑ni3j2∣i∑μ(j)(n1)j1∑nμ(j)j2∣i∑i2−j1∑nμ(j)j2∣i∑i3(n1)j1∑nμ(j)t1∑j2nt2j4−j1∑nμ(j)t1∑j2nt3j6i1∑nμ(i)j1∑i2n(i4j2(n1)−i6j3)
